Question

PLZ I REALLY NEED HELP 15 POINTS

Find the x-intercept and the y-intercept of the graph of the equation 9x + 21y = 16. Then graph the equation.

pick from the options below

Answer 1

Answer : The The x-intercept and the y-intercept of the graph of the equation is,
`x=(16)/(9)` and
`y=(16)/(21)`

Step-by-step explanation :

The given equation is:

`9x+21y=16`

To calculate the x-intercept and the y-intercept of the graph of the equation, first we are taking value of x = 0 and then y = 0.

When x = 0 then value of 'y' is:

`9x+21y=16`

`9(0)+21y=16`

`0+21y=16`

`21y=16`

`y=(16)/(21)`

When y = 0 then value of 'x' is:

`9x+21y=16`

`9x+21(0)=16`

`9x+0=16`

`9x=16`

`x=(16)/(9)`

The x-intercept and the y-intercept of the graph of the equation is,
`x=(16)/(9)` and
`y=(16)/(21)`

The correct graph is shown below.

Answer 2

To find the X intercept, replace y with 0 and solve for x:

9x + 21(0) = 16

9x = 16

x = 16/9

To find the Y intercept, replace x with 0 and solve for y:

9(0) + 21y = 16

21y = 16

y = 16/21

X-intercept is 16/9

y intercept is 16/21