Question

What is the 8th term in a geometric sequence where the first term is equal to 4 and the common ration is 2?

Answer 1

512

Explanation:

1st term =a

common ratio = r

a*r with the exponent n-1

a=4 r=2 n=8

8th term 4*(2 at the seventh power)= 512

OR

1st term :4

2nd term = 4*2=8

3rd term 8*2=16

4th term 12*2=32...............8th term 256*2=512