Question

Perform the following conversions:

(a) 68°F (a pleasant spring day) to °C and K.
(b) =164°C (the boiling point of methane, the main component of natural gas) to K and °F
(c) 0K (absolute zero, theoretically the coldest possible temperature) to °C and °F.

Answer 1

a)
`20^0C` and
`293K`

b)
`437K` and
`327.2^0F`

c)
`-273^0C` and
`459.44^0F`

Step-by-step explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like
`^0C` ,
`^0F`and
`K`

These units of temperature are inter convertible.

`t^0C=(t+273)K`

`t^oC=(5)/(9)* (t^oF-32)`

`K-273=(5)/(9)* (^oF-32)`

a) 68°F (a pleasant spring day) to °C and K.

Converting this unit of temperature into
`^0C` and
`K` by using conversion factor:

`t^oC=(5)/(9)* (68^oF-32)`

`t=20^0C`

`20^0C=(20+273)K=293K`

b) 164°C (the boiling point of methane, the main component of natural gas) to K and °F

Conversion from degree Celsius to Kelvins and Fahrenheit

`164C=(5)/(9)* (t^oF-32)`

`t^0F=327.2`

`164°C=(164+273)K=437 K`

c) 0K (absolute zero, theoretically the coldest possible temperature) to °C and °F.

`K-273=(5)/(9)* (t^oF-32)`

`0-273=(5)/(9)* (t^oF-32)`

`t=-459.4^0F`

`t^K=(0-273)^0C=-273^0C`