Answer:
A
Explanation:
The area of the shaded segment
= area of sector OAB - area of ΔOAB
area of sector = area of circle × fraction of circle, that is
A = πr² × fraction of circle
= π × 6² ×
= 36π ×
= 6π units²
Area of triangle = 0.5 × 6 × 6 × sin60° = 18 ×
= 9
units²
Hence
area of shaded segment = 6π - 9
units² → A