Question

Arun spent 25% of his pocket money and has Rs 125 left how much had he at first​

Answer 1

☄Given:

• Percentage of money spend = 25%

So,percentage of money left =100%-Percentage of money spend

`\sf{\: \:\:\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 100\% - 25\%}`

`\sf{\: \:\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 75\%}`

☄To find:

• 
  `\sf{Total\:amount=?}`

☄Solution :

• 
  `\sf{Now,Let\:total\:money\:be\:x}`

Also given that:

• 
  `\sf{Money\:left=Rs.\:125}`

Now,

percentage of money left=
`\large{\sf{ (money \: left)/(total \: money) * 100}}`

`\large{\sf{ → 75 = (125)/(x) * 100}}`

`\large{\sf{ →x = (125)/(75) * 100}}`

`\large{\sf{ → x = 125× \frac {100}{75} }}`

`\large{\sf{→x=(125×100)/(75)}}`

`\large{\sf{→x=166.67}}`

____________________________

`\large{ \underline{ \overline{ \mid{ \rm{ \red{Answer→Total\:amount=Rs\:166.67}} \mid}}}}`

____________________________

Answer 2

Rs166.67

Explanation:

Let

x -----> amount of money Arun has in his pocket at the beginning

we know that

100%-25%=75%

75%=75/100=0.75

so

The linear equation that represent this situation is

0.75x=125

Solve for x

Divide by 0.75 both sides

x=125/0.75

x=Rs166.67