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The points k(-3,2) and L(3,j) are 9 units apart find j. How do I do this with simple explanation, I’m a beginner

User Asha
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1 Answer

5 votes

Answer:


j =2 \pm 3 √(5)

Explanation:

Use the distance formula:


d= \sqrt{(x_(1) - x_(2))^(2) - (y_(1) - y_(2))^(2) }

Since the two points k(-3,2) and L(3,j) are 9 units apart find j, we substitute d=9 and the coordinates to get:


9 = \sqrt{( {3 - - 3)}^(2) + (j - 2) ^(2) }


9 = \sqrt{ {6}^(2) + {(j - 2)}^(2) }


81 = 36 + {(j - 2)}^(2)


81 - 36 = {(j - 2)}^(2)


45 = {(j - 2)}^(2)

Take square root of both sides:


j= 2 \pm3 √(5)

User Drumsta
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