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1 vote
Find the product.

(3p^4)^3 · (p^2)^7

2 Answers

2 votes

Answer:


27p^(26)

Explanation:

Let's start defining some properties about exponents.

In the properties, we use a,b,c where a,b,c ∈ IR.


(a.b)^(c)=(a^(c)).(b^(c)) (I)

This means, that we can distribute the exponent respect a multiplication.


(a^(b))^(c)=a^((b.c)) (II)

And finally


(a^(b)).(a^(c))=a^((b+c)) (III)

Using this three properties we are going to solve the exercise :


(3p^(4))^(3).(p^(2))^(7)=(3^(3)).(p^(4))^(3).(p^(14))

We used properties (I) and (II)


3^(3).(p^(4))^(3).(p^(14))=27.(p^(12)).(p^(14))=27p^(26)

The final step is to use property (II) again and the property (III)

User Linder
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Answer:

Explanation:

Good evening ,

Look at the photo below for the answer.

Find the product. (3p^4)^3 · (p^2)^7-example-1
User Stuyam
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