Question

I need help on these two problems.

Answer 1

Part 1)
`A=16\pi\ km^(2)`

Part 2)
`A=196\ mi^(2)`

Explanation:

Part 1) Find the area of the circle

we know that

The area of the circle is equal to

`A=\pi r^(2)`

where

r is the radius of the circle

we have

`r=4\ km`

substitute

`A=\pi (4)^(2)`

`A=16\pi\ km^(2)`

Part 2) Find the area of triangle

The area of triangle is equal to

`A=(1)/(2)(b)(h)`

where

b is the base and h is the height of triangle

we have

`b=20\ mi`

`h=19.6\ mi`

substitute

`A=(1)/(2)(20)(19.6)`

`A=196\ mi^(2)`