Answer:
![f_((t))=325(0.87)^(t)](https://img.qammunity.org/2020/formulas/physics/high-school/qesawv1qv77ta7whumftt4p8axn6hiv47d.png)
Step-by-step explanation:
If we have an initial amount of a radioactive material or substance, which is
, and we also are told this amount decays
each year, this means each year
of the substance remains:
![100\%-13\%=87\%=0.87](https://img.qammunity.org/2020/formulas/physics/high-school/rrpj2h6uitshmipby7xw2d82pcffxksdf9.png)
To understand it better:
Year 1:
![325(87\%)=325(0.87)](https://img.qammunity.org/2020/formulas/physics/high-school/7gy6mre852fazygr81xf309rnrozouq4pj.png)
Year 2:
![325(0.87)(0.87)=325(0.87)^(2)](https://img.qammunity.org/2020/formulas/physics/high-school/uqs4748kflm47d1771y39ce573xxj5y1fx.png)
Year 3:
![325(0.87)(0.87)(0.87)=325(0.87)^(3)](https://img.qammunity.org/2020/formulas/physics/high-school/q159mjxybm7l941gjwxe5bwsekl9fhu94s.png)
and so on until year
:
Year t:
![325(0.87)^(t)](https://img.qammunity.org/2020/formulas/physics/high-school/1oo8fx0ysfzsfyogf2m5l0b4dr6uool70w.png)
Therefore, the function tha best describes this radiation decay situation is:
![f_((t))=325(0.87)^(t)](https://img.qammunity.org/2020/formulas/physics/high-school/qesawv1qv77ta7whumftt4p8axn6hiv47d.png)