Apply Newton's second law to the car's motion:
F = ma
F = net force, m = mass, a = acceleration
The net force F is the difference of the force the car exerts on the road and the frictional/air drag forces:
F = 2150N - 225N
F = 2128N
Back to F = ma
Given values:
F = 2128N, a = 1.50m/s²
Plug in and solve for m:
2128 = m(1.50)
m = 1420kg