Question

Find the slope of the line which is perpendicular to the line 7 x + 11 Y - 2=0​

Answer 1

`\huge\boxed{slope=-(7)/(11)}`

Explanation:

METHOD 1

The slope-intercept form of an equation of a line:

`y=mx+b`

`m` - slope

`b` - y-intercept

We have the equation in the general form
`(Ax+By+C=0)`.

Convert to the slope-intercept form:

`7x+11y-2=0` subtract 7x from both sides

`11y-2=-7x` add 2 to both sides

`11y=-7x+2` divide both sides by 11

`y=-(7)/(11)x+(2)/(11)`

METHOD 2

The general form of an equation of a line:

`Ax+By+C=0`

The slope:

`m=(-A)/(B)`

We have

`7x+11y-2=0\\\\A=7;\ B=11;\ C=-2`

Substitute:

`m=(-7)/(11)=-(7)/(11)`