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A line has a y-intercept at (0,−15) and contains the point (−4,−3). What is the equation of the line in slope-intercept form?

User Carefacerz
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1 Answer

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Answer:
y=-3x-15

Explanation:

The equation of the line in Slope-Intercept form is:


y=mx+b

Where "m" is the slope and "b" the y-intercept.

Since the given line has a y-intercept at (0,-15), then:


b=-15

The formula for calculate the slope is:


m=(y_2-y_1)/(x_2-x_1)

Knowing that the given line contains the points (0,-15) and (-4,-3), we can calculate the slope. This is:


m=(-15-(-3))/(0-(-4))=-3

Substituting values into
y=mx+b, we get that the equation of the line in Slope-Intercept form is:


y=-3x-15

User Xxddoo
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