Question

-7x-11=-3y
-9x+19+8y=0
How do I evaluate this equation?​

Answer 1

x= -5

y = -8

Explanation:

we have:

-7x-11=-3y equation 1

-9x+19+8y=0 equation 2

using equation 1 we have:

-7x-11=-3y

3y - 11 = 7x

x =
`(3y-11)/(7)` equation 3

using equation 3 in equation 2 we have:

`-9((3y-11)/(7)) +19+8y=0`

`-9((3y-11)/(7)) +19+8y=0\\\\(-27)/(7)y +(99)/(7)+19+8y = 0\\\\(29)/(7)y +(232)/(7) = 0\\\\(29)/(7)y = - (232)/(7)\\\\y = (-232)/(29) \\\\y= -8`

so we have:

`x = (3*(-8)-11)/(7)\\\\x= (-24-11)/(7)\\\\x = -5`