Answer:
Option A,
%
Step-by-step explanation:
Number of chickens having featherless legs

Number of chickens having feathered legs


Frequency of chickens having featherless legs


Frequency of alleles for featherless legs

As per first equation of Hardy Weinberg-

Substituting the given values we get -

As per second equation of Hardy Weinberg-

Substituting the given values we get -
%