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In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherless legs. How many chickens are heterozygous for the “feathered leg” allele? Assume the population is in Hardy-Weinberg equilibrium. In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherless legs. How many chickens are heterozygous for the “feathered leg” allele? Assume the population is in Hardy-Weinberg equilibrium. 32 36 64 72 Not enough information is provided.

2 Answers

2 votes

Answer:

Chickens have legs

Step-by-step explanation:

they just do

User Tie
by
5.6k points
4 votes

Answer:

Option A,
32%

Step-by-step explanation:

Number of chickens having featherless legs
= 128

Number of chickens having feathered legs
= 200-128
= 72

Frequency of chickens having featherless legs


= q^(2)


q^(2) = (128)/(200)\\q^(2) = 0.64

Frequency of alleles for featherless legs


= \sqrt{q^(2)} \\= √(0.64) \\= 0.8

As per first equation of Hardy Weinberg-


p+q=1

Substituting the given values we get -


p = 1-0.8\\p=0.2

As per second equation of Hardy Weinberg-


p^(2) + q^(2) + 2pq=1

Substituting the given values we get -


0.64+0.04+2pq=1\\2pq=1-(0.64+0.04)\\2pq= 0.32\\2pq=32%

User Ezg
by
5.2k points