Question

The natural abundances of elements in the human body, expressed as percent by mass, are oxygen (O), 65 percent; carbon (C), 18 percent; hydrogen (H), 10 percent; nitrogen (N), 3 percent; calcium (Ca), 1.6 percent; phosphorus(P), 1.2 percent; all other elements, 1.2 percent. Calculate the mass in grams of each element in the body of a 62-kg person.

Answer 1

Answer: The mass of oxygen is 40300 g, hydrogen is 11160 g, nitrogen is 6200 g, calcium is 1860 g, phosphorus is 992 g and other elements is 744 g in the body of 62 kg person.

Step-by-step explanation:

We are given:

Mass of body = 62 kg = 62000 g (Conversion factor: 1 kg = 1000 g)

• For Oxygen:

Mass percent of oxygen = 65 %

This means that 65 grams of oxygen is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of oxygen present is 65 grams.

So, in 62000 grams of human body, the mass of oxygen present will be =
`(65g)/(100g)* 62000g=40300g`

Mass of oxygen present = 40300 g

• For Hydrogen:

Mass percent of hydrogen = 18 %

This means that 18 grams of hydrogen is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of hydrogen present is 18 grams.

So, in 62000 grams of human body, the mass of hydrogen present will be =
`(18g)/(100g)* 62000g=11160g`

Mass of hydrogen present = 11160 g

• For Nitrogen:

Mass percent of nitrogen = 10 %

This means that 10 grams of nitrogen is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of nitrogen present is 10 grams.

So, in 62000 grams of human body, the mass of nitrogen present will be =
`(10g)/(100g)* 62000g=6200g`

Mass of nitrogen present = 6200 g

• For Calcium:

Mass percent of calcium = 3 %

This means that 3 grams of calcium is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of calcium present is 3 grams.

So, in 62000 grams of human body, the mass of calcium present will be =
`(3g)/(100g)* 62000g=1860g`

Mass of calcium present = 1860 g

• For Phosphorus:

Mass percent of phosphorus = 1.6 %

This means that 1.6 grams of phosphorus is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of phosphorus present is 1.6 grams.

So, in 62000 grams of human body, the mass of phosphorus present will be =
`(1.6g)/(100g)* 62000g=992g`

Mass of phosphorus present = 992 g

• For other elements:

Mass percent of other elements = 1.2 %

This means that 1.2 grams of other elements is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of other elements present is 1.2 grams.

So, in 62000 grams of human body, the mass of other elements present will be =
`(1.2g)/(100g)* 62000g=744g`

Mass of other elements present = 744 g

Hence, the mass of oxygen is 40300 g, hydrogen is 11160 g, nitrogen is 6200 g, calcium is 1860 g, phosphorus is 992 g and other elements is 744 g in the body of 62 kg person.