Answer : The mass of
produced will be, 8.1 grams.
Explanation : Given,
Volume of
=

Volume of
=

Molar mass of
= 18 g/mole
First we have to calculate the moles of
and
.
As, 22.4 L volume of
present in 1 mole of

So, 50 L volume of
present in
mole of

and,
As, 22.4 L volume of
present in 1 mole of

So, 10 L volume of
present in
mole of

Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,

From the balanced reaction we conclude that
As, 2 moles of
react with 1 mole of

So, 0.45 moles of
react with
moles of

From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
.
As, 2 moles of
react to give 2 moles of

As, 0.45 moles of
react to give 0.45 moles of

Now we have to calculate the mass of
.


Therefore, the mass of
produced will be, 8.1 grams.