Answer:
Explanation:
Given that the IQs of a large population is normally distributed with a mean of 100 and an SD of 15 points.
Sample size n =40
Std error of sample =
![(\sigma)/(√(n) ) =(15)/(√(40) ) = 2.37](https://img.qammunity.org/2020/formulas/mathematics/high-school/t5i1b9ab7sa8hnv30kmtvsgzbzcsrnb6hb.png)
the approximate chance that you get exactly one person with an IQ of 130 or higher
=P(X>130)= P(Z>2) = 0.025
Since each person is independent of the other and there are only two outcomes, we get X no of persons in 40 group having iq >30 is binomial.
the approximate chance that you get at least one person with an IQ of 130 or higher=1-no one is having iq >130
=1-0.025^40
=almost 1.
=