Question

Lithium is the least dense metal known (density =0.53 g/cm^3). What is the volume occupied by 3.15 x 10^3 g of lithium?

Answer 1

Answer: The volume of lithium atom is
`5943.4cm^3`

Step-by-step explanation:

To calculate the volume of lithium we use the equation:

`\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}`

Density of lithium =
`0.53g/cm^3`

Mass of lithium =
`3.15* 10^3g`

Putting values in above equation, we get:

`0.53g/cm^3=\frac{3.15* 10^3g}{\text{Volume of lithium}}\\\\\text{Volume of lithium}=(3.15* 10^3g)/(0.53g/cm^3)=5943.4cm^3`

Hence, the volume of lithium atom is
`5943.4cm^3`

Answer 2

5943.396226 cm^3

Step-by-step explanation:

you can see the units of each data, in this case we need to know the volume, so we need that the result is in volume units (for example cm^3). We have to do the ecuation that give us this units, therefore we need to cance the units of grams.

density= mass/volume ⇒ volume= mass/ density

in units:

(g/cm^3)=g/cm^3 ⇒ cm^3=g/(g/cm3)

With numbers:

0.53 g/cm^3 = (3.15 x 10^3 g)/ V

V= volume = (3.15 x 10^3 g)/0.53 g/cm^3

V= 5943.396226 cm^3