Answer:
4
Explanation:
The first equation has 16y and the second equation has -4y where both equations are in the same form.
So we need to figure out what we can multiply to -4y such that when added to 16y will give us a sum of 0.
If you don't like that wording, maybe you are more into symbols.
We need to find k such that:
![16y+k(-4y)=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/hhuu8e1men3qwym6owh76n8kzqdqpk29s6.png)
Factor
out:
![(16+k(-4))y=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/f21q34syywukbkcfoyzt6eotjqcpbijxcm.png)
![(16-4k)y=](https://img.qammunity.org/2020/formulas/mathematics/high-school/vail27j7sk1zboznmc2a35eh58s9ntpz3h.png)
This implies 16-4k=0 since y is a variable and not always 0.
16-4k=0
Subtract 16 on both sides:
-4k=-16
Divide both sides by -4:
k=-16/-4
Simplify:
k=4
So we need to multiply the second equation by 4 so that 16y and -16y will cancel when adding the equations together.
Perhaps you like this wording more:
We need to figure out what the opposite of 16y which is -16y. The reason we wanted to know that is when you add opposites you get 0.
So how do we make -4y be -16y? We need to multiply -4y by 4 which gives you -16y.