Question

A student pours 44.3 g of water at 10°C into a beaker containing 115.2 g of water at 10°C. What are the final mass, temperature, and density of the combined water? The density of water at 10°C is 1.00 g/ml.

Answer 1

To find the final mass, temperature, and density of the combined water, we use the principle of conservation of mass. The total mass is 159.5g and the final temperature is 10°C. The density of the combined water is 1.00 g/mL.

Step-by-step explanation:

To find the final mass, temperature, and density of the combined water, we need to use the principle of conservation of mass. The total mass of the water in the beaker after pouring is the sum of the masses of the initial water and the poured water: 44.3 g + 115.2 g = 159.5 g.

The final temperature of the combined water will be the same as the initial temperature of both waters, which is 10°C.

To find the density of the combined water, we divide the total mass by the total volume. Since the density of water at 10°C is 1.00 g/mL, the volume of the combined water is equal to its mass. Therefore, the density of the combined water is 159.5 g / 159.5 mL = 1.00 g/mL.

Answer 2

Final mass = 159.5 g

Final temperature = 10 C

Final density = 1.00 g/ml

Step-by-step explanation:

Given:

Beaker 1:

Mass of water = 44.3 g

Temperature = 10 C

Beaker 2:

Mass of water = 115.2 g

Temperature = 10 C

Density of water at 10C = 1.00 g/ml

To determine:

The final mass, temperature and density of water

Calculation:

`Final\ mass\ of \ water = Beaker\ 1 + Beaker\ 2 = 44.3 + 115.2 = 159.5 g`

Since there is no change in temperature, the final temperature will be 10 C

Density of a substance is an intensive property i.e. it is independent of the mass. Hence the density of water will remain constant i.e. 1.00 g/ml