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Consider pea plants with the genotypes GgTt and ggtt. These plants can each produce how many type(s) of gametes?

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Answer:

The gametes for GgTt and ggtt would be

GgTt - GT, Gt, gT, gt

ggtt- gt, gt, gt, gt

Step-by-step explanation:

Given Genotype -

GgTt

ggtt

The allele for these two genotypes are -

GgTt - GT, Gt, gT, gt

ggtt- gt, gt, gt, gt

A punnet square representing the cross between these two genotype is given below-

GT Gt gT gt

gt GgTt Ggtt ggTt ggtt

gt GgTt Ggtt ggTt ggtt

gt GgTt Ggtt ggTt ggtt

gt GgTt Ggtt ggTt ggtt

Hence, the gametes for GgTt and ggtt would be

GgTt - GT, Gt, gT, gt

ggtt- gt, gt, gt, gt

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