202k views
5 votes
The standard molar entropy for Br2(g) is 245.46 J/(mol·K) at 25°C. Given that ΔS° = 104.58 J/K for the dissociation of one mole of Br2(g) into Br(g) at 25°C, find the standard molar entropy for Br(g) at 25°C. Enter your answer with two decimal places and no units.

1 Answer

5 votes

Answer:

The standard molar entropy for Br(g) at 25°C is 175.02J/K mol.

Step-by-step explanation:


Br_2(g)\rightarrow 2Br(g),\Delta S^o=104.58 J/K


\Delta S^(o)_(m,Br_2)=245.46 J/(mol/K)


\Delta S^o=2 mol* \Delta S^(o)_(m,Br) - 1 mol*\Delta S^(o)_(m,Br_2)


\Delta S^o= \sum \Delta S^(o)_(Products)-\sum \Delta S^(o)_(reactants)


104.58 J/K=2 mol* \Delta S^(o)_(m,Br) -1 mol* 245.46 J/(mol/K)


2 mol* \Delta S^(o)_(m,Br)=350.04J/K


\Delta S^(o)_(m,Br)=175.02J/K mol

The standard molar entropy for Br(g) at 25°C is 175.02J/K mol.

User Zuza
by
5.6k points