Answer:
D. The star is approaching Earth.
Step-by-step explanation:
As we know by the doppler's effect of light that
![(\Delta \\u)/(\\u) = (v)/(c)](https://img.qammunity.org/2020/formulas/physics/college/48i6ga3ei9odkisvlgsypryl4sp6c24kwa.png)
here we know that
= change in frequency
here we know that the wavelength of light coming from the star is decreased so the frequency will increase
![\Delta \\u = (c)/(\lambda') - (c)/(\lambda)](https://img.qammunity.org/2020/formulas/physics/high-school/fy8j3kfxofe3sx0utn5d5xhqbtmt7keroq.png)
![\Delta \\u =(3* 10^8)((1)/(6.56186 * 10^(-7)) - (1)/(6.563 * 10^(-7)))](https://img.qammunity.org/2020/formulas/physics/high-school/6bnioooqyk527zrvdf89k2trcekysca4i1.png)
![\Delta \\u = 7.9414 * 10^(10) Hz](https://img.qammunity.org/2020/formulas/physics/high-school/e7apki2ic74qo0hgixo3a74avcoz5hd971.png)
now we have
![(7.9414 * 10^(10))/(\\u) = (v)/(c)](https://img.qammunity.org/2020/formulas/physics/high-school/dwiw82sc4weipv8h9fn767nn71jait5595.png)
here we know that
![\\u = (3* 10^8)/(6.563 * 10^(-7)) = 4.57 * 10^(14) Hz](https://img.qammunity.org/2020/formulas/physics/high-school/pewzms1se8pgw4vqx8qm8t90ir3wo9b9hx.png)
now we have
![v = 5.2 * 10^4 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/lztr09osl7fjin853to2e2m2mvnoe69tpf.png)
So here correct answer is
D. The star is approaching Earth.