Answer:
years
Step-by-step explanation:
Given-
Half life of
C
years
As we know -

Where
Mass of radioactive carbon after a time period "t"
initial mass of radioactive carbon
radioactive decay constant
time
First we will find the value of "k"

On solving, we get -

Now, when mass of 14C becomes
% of the plant material on earth today, then its age would be
years