Answer:
Combustion energy for one mole of ethylene = 1410.51 kJ/mol
Step-by-step explanation:
Given data
heat capacity of bomb calorimeter = 2.47kJ/K
![\Delta T = 2.14 K](https://img.qammunity.org/2020/formulas/physics/high-school/dyuu1f8l6nun150pq3cp8vbl8xad9ahsy7.png)
molecular weight of
![C_2H_4 = 2*12.01+1.008*4=28.052](https://img.qammunity.org/2020/formulas/physics/high-school/cda14mp2wwwv1se15kfjo66na63fh2dx10.png)
Total energy released after burning 0.105 g sample is = 2.47 *2.14 =5.28 kJ
Combustion energy for one mole of ethylene
![= (5.28 *28.05)/(0.105)](https://img.qammunity.org/2020/formulas/physics/high-school/iytiwwej1xsb4jt28g0v83v397mujhc7ri.png)
= 1410.51 kJ/mol