Question

Calculate these masses.

(a) What is the mass of 6.00 cm3 of mercury, density= 13.5939 g/cm3?
(b) What is the mass of 25.0 mL octane, density= 0.702 g/cm3?

Answer 1

A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g

B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g

1mL = 1cm3

Answer 2

(a)
`m = 81.6g`

(b)
`m = 17.6g`

Step-by-step explanation:

Hello,

In this case, we consider the formula of density and solve for the required mass in each statement:

`\rho =(m)/(V) \\m=\rho *V`

In such a way we compute them as:

(a)
`m=6.00cm^3*13.5939g/cm^3=81.6g`

(b)
`m=25.0 mL*(1cm^3)/(1mL)*0.702g/cm^3 =17.6g`

Best regards.