Answer:
So Bob provide maximum impulse to the car
Step-by-step explanation:
As we know that impulse is defined as change in momentum
so here we have
![F = (\Delta P)/(\Delta t)](https://img.qammunity.org/2020/formulas/physics/middle-school/89pqaojfauj2kxu4ao530oiwiu2scwis5g.png)
![F\Delta t = \Delta P](https://img.qammunity.org/2020/formulas/physics/high-school/67algxng4623x7y49fz6oh1gml4ggo01pr.png)
so here we can say that
![impulse = F\Delta t](https://img.qammunity.org/2020/formulas/physics/high-school/w8kxvslc74v0yahqzuzobpvp0il20goeu1.png)
1), Arnold exerts a force of 300 N for three seconds,
So impulse due to force of Arnold
![Impulse = 300 * 3](https://img.qammunity.org/2020/formulas/physics/high-school/i513fhyqkwriix8wjwc8bsdo390tjjgcok.png)
![Impulse = 900 Ns](https://img.qammunity.org/2020/formulas/physics/high-school/izfnjzzovr6c54p0szcux6xvo8fwesei3s.png)
2). Bob exerts a force of 500 N for two seconds,
So impulse due to force of Bob
![Impulse = 500 * 2](https://img.qammunity.org/2020/formulas/physics/high-school/cisvv4zh43iejs92ctm4ezxlei66wapqrm.png)
![Impulse = 1000 Ns](https://img.qammunity.org/2020/formulas/physics/high-school/m9g8qj7jvx4krcib9e05acpoodjby1xb0j.png)
3). Cecil exerts a force of 200 N for four seconds.
So impulse due to force of Cecil
![Impulse = 200 * 4](https://img.qammunity.org/2020/formulas/physics/high-school/flkbmg02fvqrqvpmrgz0x3mnm4nqwrww6g.png)
![Impulse = 800 Ns](https://img.qammunity.org/2020/formulas/physics/high-school/wmuyf0myy8pv52nr4ovnceh8z1jzx0bm2q.png)