Using isentropic relations for an ideal gas:
T2 = T1(P2/P1)^(k-1)/k =
300K(2000kPa/100kPa)^0.4/1.4 = 706.1K
T4 = T3(P4/P3)^(k-1)/k =
1000K(100kPa/2000kPa)^0.4/1.4 = 424.9K
Apply the first law tot he constant-pressure heat addition process produces:
q in = h3-h2 = cp(T3-T2) =
1.005kJ/kgK * (1000 - 706.1)K = 295.4 kJ/kg
q out = h4 - h1 = cP(T4-T1) =
1.005kJ/kgK * (424.9 - 300)K= 125.5 kJ/kg
Net work production:
wnet = q in - q out =
295.4 - 1125.5 = 169.9 kJ/kg
Thermal efficiency:
w net / q in =
169.9 kJ/kg / 295.4 kJ/kg = 0.575