Question

The hindenburg zeppelin contained 200,000 m^3 of hydrogen, with a density of 0.0899 kg/m^3. What is the mass of the hydrogen?

Answer 1

d=m/v

0.0899=m/200000

or,0.0899*200000=m

m=17980

Answer 2

The mass of the hydrogen is 17,980 kilograms

Step-by-step explanation:

Remember that the density of a material is a function of its mass and its volume. This means that:

`\rho=(m)/(V)`

`\rho` is the density

m is the mass of the object

V is the volume of the object

In this case we have that:

`V = 200,000\ m^3`

`\rho=0.0899\ kg/m^3`

Then:

`0.0899=(m)/(200,000)`

Now we solve the equation for m

`m=(0.0899\ kg/m^3)*(200,000\ m^3)`

`m=17,980\ kg`