Question

Identify the conjugate acid base pair
H3PO4(ag)+CO32=HCO3-(ag)+HPO42-(ag)

Answer 1

The conjugate acid-base pairs in the reaction H3PO4(aq) + CO32- → HCO3-(aq) + HPO42-(aq) are H3PO4/HPO42- and CO32-/HCO3-.

Step-by-step explanation:

In the chemical equation H3PO4(aq) + CO32- → HCO3-(aq) + HPO42-(aq), we can identify the conjugate acid-base pairs by following a few steps. First, we need to identify the substance that has donated a proton, which is the acid, and the substance that has accepted a proton, which is the base.

Phosphoric acid (H3PO4) donates a proton to become its conjugate base, hydrogen phosphate (HPO42-). On the other side, the carbonate ion (CO32-) accepts a proton to become bicarbonate (HCO3-), its conjugate acid. Therefore, the conjugate acid-base pairs in this reaction are H3PO4/HPO42- and CO32-/HCO3-.

Answer 2

H₃PO₄/H₂PO₄⁻ and HCO₃⁻/CO₃²⁻

Step-by-step explanation:

An acid is a proton donor; a base is a proton acceptor.

Thus, H₃PO₄ is the acid, because it donates a proton to the carbonate ion.

CO₃²⁻ is the base, because it accepts a proton from the phosphoric acid.

The conjugate base is what's left after the acid has given up its proton.

The conjugate acid is what's formed when the base has accepted a proton.

H₃PO₄/H₂PO₄⁻ make one conjugate acid/base pair, and HCO₃⁻/CO₃²⁻ are the other conjugate acid/base pair.

H₃PO₄ + CO₃²⁻ ⇌ H₂PO₄⁻ + HCO₃⁻

acid base conj. conj.

base acid