Answer: The given series neither converges nor diverges.
Step-by-step explanation: We are given to determine whether the following series converges or diverges :
![S=\sum_(n=0)^(\infty)(-1)^n.](https://img.qammunity.org/2020/formulas/mathematics/college/fnkuy0tky9h4yb2lthwutrmgsnt4grg1gs.png)
If the series converges, we are to find its sum.
The given series can be written as :
![1,~-1,~1,~-1,~1,~1,~~.~~.~~.](https://img.qammunity.org/2020/formulas/mathematics/college/l03zrt6m2hr7yuz047oe1zdbsb9iy2klk6.png)
We note that the given series is a geometric one with first term 1 and common ratio given by
![r=(-1)/(1)=(1)/(-1)=~~.~~.~~.~~=-1.](https://img.qammunity.org/2020/formulas/mathematics/college/uixbz0qlvd9ndve4q937ijn6sj6kc260ya.png)
We know that a geometric series with common ratio r converges if |r| <1 and diverges if |r| > 1.
Since |r| = 1 for the given series, so the series will neither converge nor diverge.
Thus, the given series neither converges nor diverges.