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If DF=9x-39 and DE=47 and EF is 3x+10 find ef
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4 votes
If DF=9x-39 and DE=47 and EF is 3x+10 find ef

User Csaba Fabian
by
6.0k points

1 Answer

6 votes

Answer:

EF = 58

Explanation:

Starting with the premise that

DF = DE + EF, then

9x - 39 = 47 + 3x + 10 ( subtract 3x from both sides )

6x - 39 = 57 ( add 39 to both sides )

6x = 96 ( divide both sides by 6 )

x = 16

Hence

EF = 3x + 10 = (3 × 16) + 10 = 48 + 10 = 58

User Secant Zhang
by
5.4k points
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