Answer with Step-by-step explanation:
Khairul deposited $600 in a bank at the end of 2010 at the rate of 3 % per annum simple interest.
simple interest=
![(P* r* t)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5llpgb00e5uvo39xn6cwvqz669ymlltpcj.png)
where P is the principal amount
r is the interest rate and t is the time
interest got till the end of 2011=
![(600* 3* 1)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j4vsoriatcxzpd6s2dfmtjmlyoa3chi1op.png)
= $ 18
Khairul deposited $400 in the same bank at the end of 2011.
At the end of 2011 total amount in his bank= $(600+18+400)
= $1018
Interest he got from end of 2011 till end of 2013=
![(1018* 3* 2)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4kq7p1s44xf0nf9pl9k9l9ni44z33mc02v.png)
= $ 61.08
Total amount in his bank at the end of 2013=$(1018+61.08)
= $ 1079.08
Hence, total amount Khairul has in his bank at the end of 2013 is:
$ 1079.08