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8 votes
8 votes
Find the domain and range of the function.

f(x) = |x-4|+3
O domain: (-∞, ∞); range: f(x)≥-3
domain: (-∞, ∞); range: f(x) ≥3
domain: x24; range: f(x) ≥ 4
Odomain f(x) ≥3; range: (-00,00)
DONE

User Teleman
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2 Answers

8 votes
8 votes

Answer:

B: domain: (-∞, ∞); range: f(x)= ≥ 3.

Step-by-step explanation:

User Cem Ikta
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11 votes
11 votes

Answer: Choice B

domain: (-∞, ∞); range: f(x) ≥ 3

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Step-by-step explanation:

The domain is the set of allowed x values. We can replace x with any real number in this case. So x is between -∞ and ∞

We can write -∞ < x < ∞ which turns into the interval notation (-∞, ∞)

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The range is the set of all possible y outputs of a function.

The smallest |x| can get is 0, and the same goes for |x-4| as well.

This means the smallest f(x) = |x-4|+3 can get is y = 0+3 = 3

Hence y ≥ 3, which is the same as saying f(x) ≥ 3

f(x) = 3 or f(x) > 3

I recommend using a tool like Desmos to graph out f(x) = |x-4|+3, and you'll see the lowest point occurs when y = 3.

User Fulaphex
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