Answer:
3
The Problem:
.
Explanation:
Based on your choices I think you mean:
.
The equivalent exponential form is:
![(x-1)^4=16](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sabhus81snmoogmungcz49com3fc9bbqw4.png)
Take the fourth of both sides:
![(x-1)=\pm 16^(1)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e1jqzujqs8qlipkab0klcxb0e3xwbrgcix.png)
( There is two answer because it was even powered.)
Simplify:
![x-1=\pm 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q7fxj9tg777z5an5qedmhx6shaitutyxbi.png)
Add 1 on both sides.
![x=1+2=3 \text{ or } x=1-2=-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vo6y6mdsz8korm0spw62ztslzwqmtw981e.png)
Since the base of logarithm can only be postive not including 1, then the answer is just x=3. As x=-1 gives the base as x-1=-1-1=-2.