Answer:
f'(x) = 8x +4h
Explanation:
For f(x) = 4x^2 +1, we have ...
f(x+h) = 4(x +h)^2 +1 = 4x^2 +8xh +4h^2 +1
Then ...
f'(x) = (f(x+h) -f(x))/h = ((4x^2 +8xh +4h^2 +1) -(4x^2 +1))/h
= (8xh +4h^2)/h
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