Question

A 53.0 kg sled is sliding on snow with μk=0.110. how much friction force does it feel?

Answer 1

57N

Step-by-step explanation:

`F_F = \mu F_N = \mu mg = 0.11 * 53 kg * 9,8 (m)/(s^(2) )`

Answer 2

Force, F = 57.134 N

Step-by-step explanation:

It is given that,

Mass of the sled, m = 53 kg

Coefficient of kinetic friction,
`\mu_k=0.11`

We need to find the force of friction felt by sled. The force of friction is given by :

`F=\mu mg`

`F=0.11* 53\ kg* 9.8\ m/s^2`

F = 57.134 N

So, the force of friction felt by the sled is 57.134 N. Hence, this is the required solution.