Question

A 53.0 kg sled is sliding on snow with μk=0.110. how much friction force does it feel?

Answer 1

57.1 N

Step-by-step explanation:

The force of friction experienced by the sled is given by:

`F_f = \mu_k N`

where

`\mu_k = 0.110` is the coefficient of friction

N is the normal reaction exerted by the snow on the sled

For a flat surface, the normal reaction is equal to the weight of the object:

N = mg

where

m = 53.0 kg is the mass of the sled

g = 9.8 m/s^2 is the acceleration of gravity

Substituting the second equation into the first one, we find:

`F_f = \mu_k m g=(0.110)(53.0)(9.8)=57.1 N`