Question

a circle with a radius of 3 cm sits inside a circle with radius of 5 cm. what is the area of the shaded region​

Answer 1

16π

Explanation:

Area of the larger circle:

πr²

π(5)²

25π

Area of the smaller circle:

πr²

π(3)²

9π

Subtract the two:

25π-9π=16π

Answer 2

For this case we have that the area of the shaded region is given by the subtraction of areas of both circles. That is to say:
`A_ {s} = \pi * (r_ {1}) ^ 2- \pi * (r_ {2}) ^ 2`

Where:

`r_ {1}:` It is the radius of the major circle

`r_ {2}`: It is the radius of the smaller circle

According to the data we have:

`A_ {s} = \pi * (5) ^ 2- \pi * (3) ^ 2\\A_ {s} = \pi * 25- \pi * 9\\A_ {s} = 16 \pi`

Taking
`\pi = 3.14`

`A_ {s} = 50.24`

So, the area of the shaded region is
`50.24 \ cm ^ 2`

Answer:

`50.24 \ cm ^ 2`