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Technetium-99m has a half-life of 6.01 hours. If a patient injected with technetium-99m is safe to leave the hospital once 75% of the dose has decayed, when is the patient allowed to leave?

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Answer:

The patient is allowed to leave after 12.02 hours from the time of ingestion of the medicine.

Step-by-step explanation:


\lambda =\frac{0.693}{t_{(1)/(2)}}


A=A_o* e^(-\lambda t)

Where:


\lambda= decay constant


A_o =concentration left after time t


t_{(1)/(2)} = Half life of the sample

Half-life of Technetium-99m =
t_{(1)/(2)}= 6.01 hours.


\lambda =(0.693)/(6.01 hour)=0.1153 (hour)^(-1)


A_o=x

75% of medic en must have been decayed before leaving the hospital. Then percentage of left over concentration of medicine will be: 100% - 75% = 25%


A=25\%of x=0.25x

Time elapsed during this process= t


0.25x=x* e^{-0.1153 (hour)^(-1)* t}

t = 12.02 hours

The patient is allowed to leave after 12.02 hours from the time of ingestion of the medicine.

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