For this case we have the following system of equations:
![12x + 6y = 120\\4x + y = 30](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fm98abv9ptzrc24636h3775dqxc1vj9wnn.png)
We must solve the system by the method of elimination. To do this we multiply the second equation by -3, then:
![12x + 6y = 120\\-12x-3y = -90](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e1d5gm82cyuspf1qn6nhkkbeucdv1ufk6t.png)
We add both equations:
![12x-12x + 6y-3y = 120-90\\3y = 30\\y = \frac {30} {3}\\y = 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fot3mw5ipixhc47dpdf8ngtexjmv4oo9l6.png)
We find the value of "x":
![4x + y = 30\\4x + 10 = 30\\4x = 30-10\\4x = 20\\x = \frac {20} {4}\\x = 5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kfzvr00bxgn8nf1va69u5kvk5uo42qsdnl.png)
Thus, the solution of the system is:
![(x, y) :( 5,10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l5lnejwy4oecx9dxp48neazsv9r0qubxqw.png)
We verify:
![12 (5) +6 (10) = 120\\60 + 60 = 120\\120 = 120](https://img.qammunity.org/2020/formulas/mathematics/middle-school/59z5wc5iwz8j1qsa6clkfwuybqwvs4t7t6.png)
Is fulfilled!
![4 (5) + 10 = 30\\20 + 10 = 30\\30 = 30](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aa1focfhb8afc5osfj4kkcrnlarv1pihen.png)
Is fulfilled!
Answer:
![(x, y) :( 5,10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l5lnejwy4oecx9dxp48neazsv9r0qubxqw.png)