Question

How to solve the problem (2/3) to the 5 power

Answer 1

`\large\boxed{(32)/(243)}`

Explanation:

In this question, we would simply solve 2/3 to the power of 5.

This would look like this:

`(2)/(3)^5\\\\\text{This is the same as:}\\\\(2)/(3)*(2)/(3)*(2)/(3)*(2)/(3)*(2)/(3)`

You would now solve it.

Solve:

`(2)/(3)*(2)/(3)*(2)/(3)*(2)/(3)*(2)/(3)\\\\(2*2*2*2*2)/(3*3*3*3*3)=(32)/(243)\\\\\large\boxed{(32)/(243)}`

When you're done solving, you should get 32/243.

I hope this helped you out.

Good luck on your academics.

Have a fantastic day!

Answer 2

(2/3)^ 5

2*2*2*2*2= 32 ( Multiply)

3*3*3*3*3=243 ( Multiply)

32/243

Answer: 32/243