Question

Maria has eight black marbles, fourteen clear marbles, and twelve blue marbles in a bag. If she picks three marbles at random, without replacement, what is the probability that she will select a blue marble first, then a clear marble, then another blue marble?

Answer 1

7/136

Explanation:

To find the probability in this case, you have to do 12 ( the number of blue marbles ) / 34 ( the total number of marbles ) X 14 ( the number of clear marbles ) / 33 (total number of marbles after one is taken away) X 11 ( the number of blue marbles after a blue marble is taken away ) / 32 ( the number of marbles left after two is taken away ). The answer is 42/816, which reduces into 7/136.

Answer 2

The probability is 0.0514.

Explanation:

Maria has 8 black marbles, 14 clear marbles, and 12 blue marbles in a bag.

Total marbles are =
`8+14+12=34`

The requires probability is :

`(12)/(34) *(14)/(33) *(11)/(32)`

=
`(1848)/(35904)`

= 0.0514