Question

What mass of 2-bromopropane could be prepared from 25.5 g of propene? Assume a 100% yield of product.

Answer 1

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene

Step-by-step explanation:

`C_3H_6+HBr\rightarrow C_3H_7Br`

Moles of propene =
`(25.5 g)/(39 g/mol)=0.6538 mol`

According to reaction, 1 mole of propene gives 1 mole of propane.

Then 0.6538 moles of bromo-propane will give:

`0.6538 mol* 120 g/mol=78.46 g`

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene.