Question

An osprey's call is a distinct whistle at 2200 Hz. An osprey calls while diving at you, to drive you away from her nest. You hear the call at 2300 Hz. How fast is the osprey approaching?

I have tried this eqaution and the answer is still not correct..
vs= f+ - f-/f+ + f- (v) 2300-2200/2300+2200(343 m/s) =7.6 m/s. That is way too fast for a bird to fly? Can someone please help??

Answer 1

14.9 m /s

Step-by-step explanation:

n = n° x v /[ v -v (s) ]

n is apparent frequency , n° is source frequency,v is speed of sound and v(s)

speed of source.

2300 = 2200 x 343 / [343 -v(s)]

v (s ) = 14.9 m /s.