2 Answers

Ape · Answer 1 · 2020-08-04T19:41:32+0000

Answer: (a) 0.0656

(b) 0.00028

Explanation:

Since we have given that

Probability that a randomly selected 5-year old male horned beetle will live to be 6 years old = 0.25624

If there are

Number of male horned beetles = 2

So, probability that two randomly selected 5-year-old male horned beetles will live to be 6 years old is given by

$(0.25624)^2\\\\=0.0656$

If number of male horned beetles = 6

So, probability that six randomly selected 5-year-old male horned beetles will live to be 6 years old is given by

$(0.25624)^6\\\\=0.00028\\$

Hence, (a) 0.0656

(b) 0.00028

Elliott Hughes · Answer 2 · 2020-08-10T01:47:29+0000

Answer:

(a) The probability that two randomly selected 5-year-old male horned beetles will live to be 6 years old is 0.06566.

(b) The probability that six randomly selected 5-year-old male horned beetles will live to be 6 years old is 0.000283.

Explanation:

It is given that the probability that a randomly selected 5-year-old male horned beetle will live to be 6 years old is 0.25624.

(a)

We need to find the probability that two randomly selected 5-year-old male horned beetles will live to be 6 years old.

$P=0.25624* 0.25624=(0.25624)^2=0.0656589376\approx 0.06566$

Therefore the probability that two randomly selected 5-year-old male horned beetles will live to be 6 years old is 0.06566.

(b)

We need to find the probability that six randomly selected 5-year-old male horned beetles will live to be 6 years old.

$P=0.25624* 0.25624* 0.25624* 0.25624* 0.25624* 0.25624=(0.25624)^6=0.000283061988948\approx 0.000283$

Therefore the probability that six randomly selected 5-year-old male horned beetles will live to be 6 years old is 0.000283.

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