Question

A solenoid of length 2.50 m and radius 1.70 cm carries a current of 0.110 A. Determine the magnitude of the magnetic field inside if the solenoid consists of 2200 turns of wire.

Answer 1

magnetic field is 0.122 mT

Step-by-step explanation:

Given data

length = 2.50 m

radius = 1.70 cm

current = 0.110 A

turns of wire = 2200

to find out

magnitude of the magnetic field

solution

we know the relation of current turn and length with magnetic field i.e

magnetic field = ( μ × turn × current ) / length

here μ is permeability

magnetic field = ( μ × turn × current ) / length

magnetic field = ( 4π ×
`10^(-7)` × 2200 × 0.110) / 2.50

magnetic field = ( 4π ×
`10^(-7)` × 2200 × 0.110) / 2.50

magnetic field = 0.000122

so magnetic field is 0.122 mT