Question

A solar cell that transforms 300 J of light energy into 45 J of electrical energy and 255 J of wasted energy. whats the efficiency

Answer 1

15%

Step-by-step explanation:

Step one:

Given data

Energy source= 300J

Useful energy = 45J

Waste energy = 255J

Required

The efficiency of the solar system

Step two:

The efficiency is computed by factoring only the useful work and the energy source

Efficiency= 45/300*100

Efficiency= 0.15*100

Efficiency= 15%