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A solution contains 100.0 g water, 10.0 g NaCl, and 15.0 g methanol. What is the masspercent of methanol in the solution?

User Himujjal
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1 Answer

3 votes

Answer:

12% is the mass percent of methanol in the solution.

Step-by-step explanation:

Mass of water = 100.0 g

Mass of NaCl = 10.0 g

Mass of methanol = 15.0 g

Mass of the solution = 100.0 g+ 10.0 g+ 15.0 g = 125.0 g


Mass\%=\frac{\text{mass of compound}}{\text{Total mass of solution}}* 100


Methanol\%=(15.0 g)/(125.0 g)* 100=12\%

12% is the mass percent of methanol in the solution.

User Dace
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