Question

Elemental S reacts with O2 to form SO3 according to the reaction

2S+3O2→2SO3

What is the theoretical yield of SO3 produced by 8.79 g of S?
Express your answer numerically in grams.

Answer 1

theoretical yield 22.0grams

Step-by-step explanation:

molecular wt - S: 32, O:16

in reaction 2S+3O2→2SO3

S and SO3 has the same molar ratio

mass of S/molecular wt of S = mass of SO3 / molecular wt of SO3

mass of SO3 = mass of S/molecular wt of S * molecular wt of SO3

= 8.79 / 32 * (32+16*3)

= 8.79 / 32 * 80

= 22.0grams

Answer 2

Step-by-step explanation:

Given the reaction equation

2S+3O2→2SO3

2 moles of S will produce 2 moles of SO3

Molecular mass of S is 32g, so 8.79 g of S = 8.79/32 = 0.2747 moles

It will yield 0.2747 moles of SO3

Molecular mass of SO3 is 32+16*3 = 80g

0.2747 moles of SO3 = 0.2747*80 = 22g

The theoretical yield of SO3 is 22 grams.